Angular Momentum Anyway

When Is The Angular Momentum Of A System Constant

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You're sitting in a physics lecture, or maybe staring at a textbook at 2 a.m., and the professor drops the line: "Angular momentum is conserved.

Cool. Great. When?

Because "always" is the wrong answer. And "never" is definitely the wrong answer. The real answer lives in the messy middle — and that's where most students (and honestly, a lot of engineers) get tripped up.

Let's clear it up once and for all.

What Is Angular Momentum Anyway

Before we talk about when it stays constant, we need to be crystal clear on what it actually is.

Angular momentum (L) is the rotational analog of linear momentum. For a single particle, it's defined as the cross product of the position vector (r) and linear momentum (p):

L = r × p

For a rigid body rotating about a fixed axis, it simplifies to:

L = Iω

Where I is the moment of inertia and ω is the angular velocity. Simple enough.

But here's the thing — angular momentum isn't a scalar. It's a vector. Direction matters. That said, the right-hand rule isn't just a cute convention; it's baked into the math. If you treat it like a number with a sign, you'll get the right answer for simple 1D rotation problems and the wrong answer for everything else.

It's Not Just "Spinning Stuff"

A common misconception: angular momentum only exists when something is visibly rotating. And nope. A particle moving in a straight line past a fixed point has angular momentum relative to that point. Because of that, it's not zero just because the path isn't circular. The magnitude is mvr sinθ*, where θ is the angle between r and v. That's why if the particle passes directly through the origin, θ is 0 or 180°, and L is zero. But offset the path? Now you've got angular momentum without a single rotation.

This distinction matters when you're analyzing systems where objects fly past each other — collisions, gravitational slingshots, particle decay.

Why It Matters / Why People Care

Conservation laws are the cheat codes of physics. Energy conservation. Momentum conservation. And angular momentum conservation. They let you solve problems without knowing the messy details of forces, torques, or interaction times.

But here's the trap: angular momentum is only conserved when the net external torque on the system is zero.

Not "when there are no forces.Day to day, " Not "when the system is isolated. " **Zero net external torque.

That's a very specific condition. And it's easier to break than you think.

Real-World Stakes

Figure skaters pull their arms in to spin faster. That's conservation of angular momentum — I goes down, ω goes up. No external torque (friction at the ice is negligible for the short term).

A collapsing star spins up into a pulsar. Same principle. Moment of inertia drops by orders of magnitude; rotation rate screams up.

But — and this is critical — if that skater digs a toe pick into the ice? In real terms, external torque. Conservation goes out the window. If the star has a magnetic field braking its rotation via stellar wind? External torque. Not conserved.

Engineers designing reaction wheels for satellites live and die by this. Gyroscopes. Flywheels. The entire attitude control system of a spacecraft assumes angular momentum conservation until* thrusters fire or magnetic torquers engage.

How It Works: The Condition for Conservation

Let's derive it properly. Not because you need the derivation for a test, but because seeing where* the condition comes from prevents mistakes.

Start with the definition for a system of particles:

L_total = Σ (r_i × p_i)

Take the time derivative:

dL_total/dt = Σ (dr_i/dt × p_i) + Σ (r_i × dp_i/dt)

The first term: dr_i/dt = v_i, and p_i = m_i v_i. Cross product of a vector with itself is zero. So that whole sum vanishes.

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The second term: dp_i/dt = F_i (net force on particle i). So:

dL_total/dt = Σ (r_i × F_i)

That sum is the net torque on the system. But F_i includes both internal and external forces.

τ_net = τ_ext + τ_int

Newton's third law: internal forces come in equal-and-opposite pairs. If those forces are central (act along the line connecting the particles), their torques cancel exactly. τ_int = 0.

So:

dL_total/dt = τ_ext

Angular momentum is constant if and only if the net external torque is zero.

That's the whole ballgame. Everything else is just applying this to specific situations.

The "About What Point?" Trap

Here's where it gets subtle. Torque depends on your choice of origin. τ = r × F. Shift the origin, r changes, τ changes.

So angular momentum conservation is origin-dependent.

A system might have zero net external torque about point A, but non-zero torque about point B. In that case, L is conserved about A but not about B.

Example: A projectile in free flight (no air resistance). Gravity is the only force. About the launch point? Torque is non-zero (r × mg ≠ 0 generally). L is not conserved. About the center of mass? Gravity acts at the CM, so r = 0, torque is zero. **L is conserved about the CM.

Wait — but the projectile isn't rotating. Its angular momentum about its own CM is zero (if we ignore spin). Trivially conserved. Boring.

Better example: Two masses connected by a spring, floating in space, oscillating. No external forces. L is conserved about any point. Because τ_ext = 0 everywhere.

Now add a uniform gravitational field. **L about CM is conserved.Torque about the CM? ** Torque about an arbitrary fixed point on the ground? Zero. Non-zero. Net force = Mg downward. **L about that point is not conserved.

This isn't a contradiction. Here's the thing — it's just math. Pick your origin wisely.

Internal Torques Can Redistribute L — But Not Change Total L

Two astronauts floating in space, connected by a rope. Internal forces. No external torque. On top of that, they pull themselves together. Total L constant.

But — each astronaut's individual* angular momentum changes. The rope exerts torques on them. In practice, internal torques redistribute angular momentum within* the system. They just can't change the total*.

This is why reaction wheels work. The wheel spins one way; the satellite spins the other. Total L stays zero (if it started at zero). The motor applies internal torque. No external torque needed.

Common Mistakes / What Most People Get Wrong

1. Confusing "No External Force" with "No External Torque"

A uniform force field (like gravity near Earth's surface) exerts a net force but zero torque about the center of mass*. L about CM is conserved even though linear momentum is not.

Conversely, a single force applied off-center creates torque but might not change net force much. Different conditions.

2. Assuming Central Forces Are the Only Internal Forces

We said internal torques cancel if forces are central (along the line connecting particles). What if they're not?

Magnetic forces between moving charges are not central. In practice, they violate Newton's third law in the simple form (action-reaction along the line of centers). The field itself carries angular momentum.

If you only count mechanical angular momentum of the particles, it's not conserved. Day to day, you have to include the field's angular momentum. Total (mechanical + field) L is conserved.

This bites people in E&M. A lot.

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playontag

Staff writer at playontag.com. We publish practical guides and insights to help you stay informed and make better decisions.

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